How to check anagrams using regex

Notes on Le Wagon Regular Expressions Anagrams exercise

For this exercise we want to write a method that will check if two strings are anagrams.

def anagrams?(a_string, another_string)
  a_string = a_string.downcase.chars.sort.join.gsub(/\s+/, "").gsub(/[^0-9a-zA-Z]/, "")
  another_string = another_string.downcase.chars.sort.join.gsub(/\s+/, "").gsub(/[^0-9a-zA-Z]/, "")
  return a_string == another_string

For this first method we start out with creating two variables. These are called a_string and another_string respectivley. We apply the same logic to both of the given arguments.

We start by calling:

Now we can return true if a_string is equal to another_string

To demonstrate how this works lets take the example of the word POST and the word SPOT

POST -> ['p', 'o', 's', 't'] -> ['o', 'p', 's', 't'] -> "opst" SPOT -> ['s', 'p', 'o', 't'] -> ['o', 'p', 's', 't'] -> "opst"

This is am anagram because both results have returned in the same order.

What if we wanted to make our method faster by improving its Time Complexity? (Time taken to complete a method)

To do this we might want to use a hash. Lets create a method that will create our hash which we can use to store data inside.

def create_hash(word)
  word = word.downcase.chars.sort.join.gsub(/\s+/, "").gsub(/[^0-9a-zA-Z]/, "")
  new_hash = {}
  word.each_char do |char|
    if new_hash.key?(char)
      new_hash[char] += 1
      new_hash[char] = 1
  return new_hash.values

This array takes one argument of word. We can then create a new variable which will be equivilent to downcasing the word and substituting any characters other than letters and numbers. We also set our new_hash to empty {}.

Finally we return the new_hash.values. This gives us a new array which is populated by groups of values from the hash.

We need to modify our first method so that we can take advantage of the hash we just created.

def anagrams_on_steroids?(a_string, another_string)
  a_hash = create_hash(a_string)
  another_hash = create_hash(another_string)
  return a_hash == another_hash

Here, we are setting up two variables and calling our create_hash method inside each of them. We give it the required arguments of a_string and another_string respectively. We then return true or false depending on if the a_hash and another_hash variables are the same.

The flow of this can be confusing so to recap: